v^2+12v+17=0

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Solution for v^2+12v+17=0 equation:


Simplifying
v2 + 12v + 17 = 0

Reorder the terms:
17 + 12v + v2 = 0

Solving
17 + 12v + v2 = 0

Solving for variable 'v'.

Begin completing the square.

Move the constant term to the right:

Add '-17' to each side of the equation.
17 + 12v + -17 + v2 = 0 + -17

Reorder the terms:
17 + -17 + 12v + v2 = 0 + -17

Combine like terms: 17 + -17 = 0
0 + 12v + v2 = 0 + -17
12v + v2 = 0 + -17

Combine like terms: 0 + -17 = -17
12v + v2 = -17

The v term is 12v.  Take half its coefficient (6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
12v + 36 + v2 = -17 + 36

Reorder the terms:
36 + 12v + v2 = -17 + 36

Combine like terms: -17 + 36 = 19
36 + 12v + v2 = 19

Factor a perfect square on the left side:
(v + 6)(v + 6) = 19

Calculate the square root of the right side: 4.358898944

Break this problem into two subproblems by setting 
(v + 6) equal to 4.358898944 and -4.358898944.

Subproblem 1

v + 6 = 4.358898944 Simplifying v + 6 = 4.358898944 Reorder the terms: 6 + v = 4.358898944 Solving 6 + v = 4.358898944 Solving for variable 'v'. Move all terms containing v to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + v = 4.358898944 + -6 Combine like terms: 6 + -6 = 0 0 + v = 4.358898944 + -6 v = 4.358898944 + -6 Combine like terms: 4.358898944 + -6 = -1.641101056 v = -1.641101056 Simplifying v = -1.641101056

Subproblem 2

v + 6 = -4.358898944 Simplifying v + 6 = -4.358898944 Reorder the terms: 6 + v = -4.358898944 Solving 6 + v = -4.358898944 Solving for variable 'v'. Move all terms containing v to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + v = -4.358898944 + -6 Combine like terms: 6 + -6 = 0 0 + v = -4.358898944 + -6 v = -4.358898944 + -6 Combine like terms: -4.358898944 + -6 = -10.358898944 v = -10.358898944 Simplifying v = -10.358898944

Solution

The solution to the problem is based on the solutions from the subproblems. v = {-1.641101056, -10.358898944}

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